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程序为：
/*
西历农历转换程式 黄晓鸣 1995,7,25
prototype: int calconv( struct convdate * );
struct convdate
{
int source; ==0 则输入日期为西历, !=0 则输入为农历
int solaryear; 输出或输入之西历年份
int solarmonth; 西历月
int solardate; 西历日
int lunaryear; 输出或输入之农历年份
int lunarmonth; 农历月
int lunardate; 农历日
int weekday; 该日为星期几 ( 0==星期日, 1==星期一, ... )
int kan; 该日天干 ( 0==甲, 1==乙, ..., 9==癸 )
int chih; 该日地支 ( 0==子, 1==丑, ..., 11==亥 )
};
呼叫时须设定 souce 的值, 若为 0 则为西历转农历, 否则为农历转西历. 然後视
输入为西历或农历来设定西历或农历的年月日. 转换後的年月日会填入结构中( 农
历或西历 ), 以及该日为星期几, 天干地支.
若函式的返回值为 0 表示没有错误, 1 为输入之年份错误, 2 为输入之月份错误,
3 为输入之日期错误.
输入之西历年须在 1937 - 2031 间
输入之农历年须在 1936 - 2030 间
若须扩充, 则增加 lunarcal[]
*/
#define firstyear 1936 /* the first year in lunarcal[] */
struct convdate
{
int source;
int solaryear;
int solarmonth;
int solardate;
int lunaryear;
int lunarmonth;
int lunardate;
int weekday;
int kan;
int chih;
};
struct taglunarcal
{
int basedays; /* 到西历 1 月 1 日到农历正月初一的累积日数 */
int intercalation; /* 闰月月份. 0==此年没有闰月 */
int baseweekday; /* 此年西历 1 月 1 日为星期几再减 1 */
int basekanchih; /* 此年西历 1 月 1 日之干支序号减 1 */
int monthdays[13]; /* 此农历年每月之大小, 0==小月(29日), 1==大月(30日)*/
};
struct taglunarcal lunarcal[] = {
, /* 1936 */
,
,
,
, /* 1940 */
,
,
,
, /* 1944 */
,
,
,
, /* 1948 */
,
,
,
, /* 1952 */
,
,
,
, /* 1956 */
,
,
,
, /* 1960 */
,
,
,
, /* 1964 */
,
,
,
, /* 1968 */
,
,
,
, /* 1972 */
,
,
,
, /* 1976 */
,
,
,
, /* 1980 */
,
,
,
, /* 1984 */
,
,
,
, /* 1988 */
,
,
,
, /* 1992 */
,
,
,
, /* 1996 */
,
,
,
, /* 2000 */
,
,
,
, /* 2004 */
,
,
,
, /* 2008 */
,
,
,
, /* 2012 */
,
,
,
, /* 2016 */
,
,
,
, /* 2020 */
,
,
,
, /* 2024 */
,
,
,
, /* 2028 */
,
,
};
#define lastyear (firstyear+sizeof(lunarcal)/sizeof(struct taglunarcal)-1)
/* 西历年每月之日数 */
int solarcal[12] = ;
/* 西历年每月之累积日数, 平年与闰年 */
int solardays[2][14] = {
,
};
/* 求此西历年是否为闰年, 返回 0 为平年, 1 为闰年 */
int getleap( int year )
{
if ( year % 400 == 0 )
return 1;
else if ( year % 100 == 0 )
return 0;
else if ( year % 4 == 0 )
return 1;
else
return 0;
}
/* 西历农历转换 */
int calconv( struct convdate *cd )
{
int leap, d, sm, y, im, l1, l2, acc, i, lm, kc;
if ( cd->source == 0 ) /* solar */
{
if ( cd->solaryear <= firstyear || cd->solaryear > lastyear )
return 1;
sm = cd->solarmonth - 1;
if ( sm < 0 || sm > 11 )
return 2;
leap = getleap( cd->solaryear );
if ( sm == 1 )
d = leap + 28;
else
d = solarcal[sm];
if ( cd->solardate < 1 || cd->solardate > d )
return 3;
y = cd->solaryear - firstyear;
acc = solardays[leap][sm] + cd->solardate;
cd->weekday = ( acc + lunarcal[y].baseweekday ) % 7;
kc = acc + lunarcal[y].basekanchih;
cd->kan = kc % 10;
cd->chih = kc % 12;
if ( acc <= lunarcal[y].basedays )
{
y--;
cd->lunaryear = cd->solaryear - 1;
leap = getleap( cd->lunaryear );
sm += 12;
acc = solardays[leap][sm] + cd->solardate;
}
else
cd->lunaryear = cd->solaryear;
l1 = lunarcal[y].basedays;
for ( i=0; i<13; i++ )
{
l2 = l1 + lunarcal[y].monthdays[i] + 29;
if ( acc <= l2 )
break;
l1 = l2;
}
cd->lunarmonth = i + 1;
cd->lunardate = acc - l1;
im = lunarcal[y].intercalation;
if ( im != 0 && cd->lunarmonth > im )
{
cd->lunarmonth--;
if ( cd->lunarmonth == im )
cd->lunarmonth = -im;
}
if ( cd->lunarmonth > 12 )
cd->lunarmonth -= 12;
}
else /* lunar */
{
if ( cd->lunaryear < firstyear || cd->lunaryear >= lastyear )
return 1;
y = cd->lunaryear - firstyear;
im = lunarcal[y].intercalation;
lm = cd->lunarmonth;
if ( lm < 0 )
{
if ( lm != -im )
return 2;
}
else if ( lm < 1 || lm > 12 )
return 2;
if ( im != 0 )
{
if ( lm > im )
lm++;
else if ( lm == -im )
lm = im + 1;
}
lm--;
if ( cd->lunardate > lunarcal[y].monthdays[lm] + 29 )
return 3;
acc = lunarcal[y].basedays;
for ( i=0; i acc += lunarcal[y].monthdays[i] + 29;
acc += cd->lunardate;
leap = getleap( cd->lunaryear );
for ( i=13; i>=0; i-- )
if ( acc > solardays[leap][i] )
break;
cd->solardate = acc - solardays[leap][i];
if ( i <= 11 )
{
cd->solaryear = cd->lunaryear;
cd->solarmonth = i + 1;
}
else
{
cd->solaryear = cd->lunaryear + 1;
cd->solarmonth = i - 11;
}
leap = getleap( cd->solaryear );
y = cd->solaryear - firstyear;
acc = solardays[leap][cd->solarmonth-1] + cd->solardate;
cd->weekday = ( acc + lunarcal[y].baseweekday ) % 7;
kc = acc + lunarcal[y].basekanchih;
cd->kan = kc % 10;
cd->chih = kc % 12;
}
return 0;
}
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