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深入讲解oracle数据库的多栏输出语句

【赛迪网-it技术报道】数据表:

id name

1 苹果汁

2 牛奶

3 蕃茄酱

4 盐

5 麻油

6 酱油

7 海鲜粉

8 胡椒粉

9 鸡

10 蟹

11 民众奶酪

12 德国奶酪

13 龙虾

14 沙茶

15 味精

16 饼干

17 猪肉

18 墨鱼

19 糖果

20 桂花糕

21 花生

22 糯米

以下是我们想要得到的结果:

id1 name1 id2 name2 id3 name3

1 苹果汁 2 牛奶 3 蕃茄酱

4 盐 5 麻油 6 酱油

7 海鲜粉 8 胡椒粉 9 鸡

10 蟹 11 民众奶酪 12 德国奶酪

13 龙虾 14 沙茶 15 味精

16 饼干 17 猪肉 18 墨鱼

19 糖果 20 桂花糕 21 花生

22 糯米

使用sql语句:

with test as(
select 1 as id, '苹果汁' as name from dual union all
select 2 as id, '牛奶' as name from dual union all
select 3 as id, '蕃茄酱' as name from dual union all
select 4 as id, '盐' as name from dual union all
select 5 as id, '麻油' as name from dual union all
select 6 as id, '酱油' as name from dual union all
select 7 as id, '海鲜粉' as name from dual union all
select 8 as id, '胡椒粉' as name from dual union all
select 9 as id, '鸡' as name from dual union all
select 10 as id, '蟹' as name from dual union all
select 11 as id, '民众奶酪' as name from dual union all
select 12 as id, '德国奶酪' as name from dual union all
select 13 as id, '龙虾' as name from dual union all
select 14 as id, '沙茶' as name from dual union all
select 15 as id, '味精' as name from dual union all
select 16 as id, '饼干' as name from dual union all
select 17 as id, '猪肉' as name from dual union all
select 18 as id, '墨鱼' as name from dual union all
select 19 as id, '糖果' as name from dual union all
select 20 as id, '桂花糕' as name from dual union all
select 21 as id, '花生' as name from dual union all
select 22 as id, '糯米' as name from dual
)
select max(decode(mod(id, 3), 1, id, '')) id1,
max(decode(mod(id, 3), 1, name, '')) name1,
max(decode(mod(id, 3), 2, id, '')) id2,
max(decode(mod(id, 3), 2, name, '')) name2,
max(decode(mod(id, 3), 0, id, '')) id3,
max(decode(mod(id, 3), 0, name, '')) name3
from test
group by trunc(rownum / 3 - 0.1, 0)
order by id1

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